Question

Please answer question #3

A string with a total length of 270.8 0.05 cm has a total mass of 12.0 t0.1g. It is fixed at one end and stretched between that end and a pulley, two points that are 159.6 t0.05 cm apart, by hanging a mass of 200.0 t0.1 g. When the string is removed from the hanging mass, that portion of the string that was between the two fixed points is 145.0 t0.05 cm. From the above information show the following calculations: 1. The linear mass density of the stretched string: 2. The percent uncertainty in the linear mass density of the stretched string With the string stretched by hanging a mass of 200.0 t 0.1 g over the pulley, a frequency generator creates a vibration in the string and the frequency for resonances are recorded for each case of an integer number of anti-nodes from 1 to 7. The frequency is plotted as a function of the integer number anti-nodes and a linear trend line fit is made of the plotted data. The slope of the trend line fit for the graph is m 6.82 t 0.062 Hz. From the above information show the following calculations: 3. From the graph's trendline fit, the linear mass density 4. From the graphs trendline fit, the percent uncertainty in the linear mass density 5. Percent difference between the two linear mass densities: PD

Answer 1

Soution: stung length 270.8 さ0.05 cm mass = 12.0 ±0.1 g t1a hixed one end and sad bebucen o endand apuuey, tao Pornto ao, 159.6±0.05 Cm apod The Gls 270.8X 159.6 5.0 oboed Sing, i)tinea mass density o the eded eling -U - 12.0 XIuS.O Crn 270.8x 1S9.6 0.05 0.05 0.05 ソ ~ o.oof