Question

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14. (7 points) The threshold frequency of a certain metal is 6.53 x 1014 Hz. If light whose wavelength is 405 nm strikes the metal surface what will be the velocity of the emitted electrons?

Answer 1

When incident a clean mtallic sunface e Hhene a place between electnon of me tal an collisim taker pho forned A pont nengy iauda func tim and the neot pant incneases the kinthe eningyelec tno New, awoTokfunctin ishe mir in incident fo ovencome the coonk roeguine to kiretic enen e with zeno Now, we knoo whene 4-c00rk functim Dntal when. k.E -0 kE= kine ic eneng Netd, the concip thorshold foegune into pichune Itis the min faegueny neede to kineHd fneguaney of Dincent pho tory COmuo photor oith tal Zeno Naw, yo = 6.5371014 Hx planck's Constanl=C 6d 6710-34 = 2.h -6.531014A6.626M10-14T 4.3A10-19 41

Now, kE=h-4 whane, C=speid light -4 Me mas 9.1M1031 -4 h=6.6610J -24 me 2 a = 405 nm =405A10-9 m he -4 9.IMo 3 C.GR67103 308 -34 - 4.3M109 -31 9-1A10 405A10-9 3-66N105 mS- emite electnono i's So, the ve 3.6C105 Mr-
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