Light of wavelength (3.222x10^-7)m is shined onto a piece of metal with a threshold frequency of (3.96x10^14)hz. How much energy do the ejected electrons have?
Answer – We are given, wavelength , λ = 3.222*10-7 m ,
threshold frequency, νo = 3.96*1014 Hz
We know the energy of ejected electrons is the difference between the energy of the photon and the work function.
We know, work function = h* νo
So, energy of ejected electron = h*c/ λ - h* νo
= 6.626*10-34J.s * 3.0*108 m.s-1 / 3.222*10-7 m - 6.626*10-34J.s *3.96*1014 Hz
= 6.17*10-19 J – 2.62*10-19 J
= 3.54*10-19 J
Energy in eV –
We know,
= 3.54*10-19 J * 6.24*1018
= 2.21 eV.
Light of wavelength (3.222x10^-7)m is shined onto a piece of metal with a threshold frequency of...
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