Question

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POS UUUJDOO ABORATORY ASSIGNMEN 1. Calculate the theoretical percentage of water for the following hydrates. (a) nickel(II) chloride dihydrate, NiCl2.2H20 INI x 58.69 = 58.64 2 CL X 35.45 - 70.90 2 H20 x 18.02 - 36.04 765. 63 2x 18.02 x 100-21.75% Had 20% 21.75% H2O (b) nickel(II) chloride hexahydrate, NiClz. 6H20 1 Ni X 59.69 58.64 2 x 35.45 = 35.45 6 120 x 18.02 = 109.12 202.26 1.555 *100 36.08% GX 18.02 x 100-53.60% H205492 202.26% 53.50% H2O 2. If an unknown hydrate, AC-XH2O, has a mass of 1.555 g before heating, and a mass of 0.994 g after heating, what is the experimental percentage of water in the hydrate? 0.566 .555-0.9949 0.56lg 236.1 36.1% H2O 3. If the anhydrous compound (AC) in the preceding problem has a molar mass of 160 g/mol. what are the water of crystallization (X) and formula for the hydrate? 36.089 H2O x 1 mol H2O 18.029 H2O2..002 mol H2O 63.929 4€ x molac - 0.3995 mol ac 2.002 mol H2O - 5.01125 0.3995 mol AC -0. Water of crystallization 5 Formula of hydrate Ac. 5 H20 Analysis of Alum

Answer 1

0 9 e 6 correct mass before heating - unknown hydrate Ac •X H20 = 1.555g = A mass after heating = 0.994g B mass of water x H₂O= AB = 0.561g y of wateiſ hy drate - mass of water (*120) Total mass of hydrate 1.555 = 36.00% 0.561 x 100 = 36.08% water moles of anhydrous compound - mass of anhydroca Асс motar mass 0.994 gm (B) 160 g/mol moles of water in hydrate = water in hydrate - = 0062 mole mass of cate (A-B) molar massed water 0.5619 - 18.02 = .03113 03113 18.02g/mol mole. 0062 mole anhydrate contains = 103113 mole water 1 - 10313 e mole 0062 water E so water of crystallization = 5(120) (2), X- Formula of hydrate = AC.5H₂O 5.02 ñ 5 mole H₂O 5