Question

10.0 g of NO and 10.0 g of O₂ react together in the following unbalancedd reaction. How many grams of NO₂ will be formed?

NO + O₂ --> NO₂

Answer 1

The balanced equation is

2 NO + O₂ -----> 2 NO₂

Number of moles of NO = 10.0 g / 30.01 g/mol = 0.333 mole

Number of moles of O2 = 10.0 g / 32.0 g/mol = 0.313 mole

From the balanced equation we can say that

2 mole of NO requires 1 mole of O2 so

0.333 mole of NO will require

= 0.333 mole of NO *(1 mole of O2 / 2 mole of NO)

= 0.157 mole of O2

But we have 0.313 mole of O2 which is in excess so O2 is an excess reactant and NO is limiting reactant

From the balanced equation we can say that

2 mole of NO produces 2 mole of NO2 so

0.333 mole of NO will produce

= 0.333 mole of NO *(2 mole of NO2 / 2 mole of NO)

= 0.333 mole of NO2

mass of 1 mole of NO2 = 46.0055 g so

the mass of 0.333 mole of NO2 = 15.3 g

Therefore, the mass of NO2 produced would be 15.3 g