Exercise C For each of the reactions listed below. use the reactions after it to determine...
Show all work and calculations. Find the ΔH for the target reaction below, given the following step reactions and subsequent ΔH values: N2H4(l) + CH4O(l) → CH2O(g) + N2(g) + 3H2 (g) 2NH3(g) → N2H4(l) + H2(g) ΔH = 22.5 kJ 2NH3(g) → N2(g) + 3H 2(g) ΔH = 57.5 kJ CH2O(g) + H2(g) → CH 4O(l) ΔH = 81.2 kJ
Answer the following questions ans please show your calculation.
= 24,7 +402.8 = 1 AH,º= -447KJ AH2O= -484KJ AH;O= -429KJ AHRO= HW12 Using the following reactions: A+B+ 2C LA +3D+ 2E 2D+B+ 2F Calculate AH for the process 4E+ 5B → 4C +6F HW13 Using the following reactions: N2(g) + O2(g) → 2NO(g) N2(g) + 3H2(g) + 2NH3(g) 2H2(8) + O2(g) → 2H20(8) Calculate AH for the process 4NH3(g) + 502(8) → 4NO(g) + 6H2O(8) AH =+180.6 kg AH,O= -91.8...
(1) Find the H for the reaction below, given the following reactions and subsequent H values: 2CO2(g) + H2O(g) → C2H2(g) + 5/202(g) CH2(g) + 2H2(g) → CHg) H2O(g) - H2(g) + 1/20, (g) C2H6(g) + 7/202(g) → 2CO2(g) + 3H2O(g) answer - 235 kJ H =-94.5 kJ H =71.2 kJ H --283 kJ (2) Find the H for the reaction below, given the following reactions and subsequent H values: N2H4(I) + H2(g) + 2NH3(g) N2H4(1) + CH4O(1) - CH2O(g)...
(ii) Calculate AH° for the reaction N2H4(1) + O2(g) → N2(g) + 2H2O(1) using the data given below: 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(1) N2O(g) + 3H2(g) → N2H4(l) + H2O(1) 2NH3(g) + O2(g) → N2H4(1) + H2O(1) H2(g) + 1/2O2(g) → H2O(1) AH° = -1010. kJ AH° = -317 kJ AH° = -143 kJ AH° = -286 kJ
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QUESTIONS
What is the molar reaction enthalpy for the reaction below: NgH4(I) + CH4 (1) #CH2O(g) + Ng(g) + 3Hg(g) given the following thermodynamic data? 2NH3(g) + N2H4(1) + H2(g) A,Hm = 22.5 kJ mol-1 2NH3(g) + N2(g) + 3H2(9) A,Hm = 57.5 kJ mol-1 CH2O(g) + H2(g) + CHAO(0) A,Hm = 81.2 kJ mol-1 0 -11.5 kJ mol-1 0 -32.8 kJ mol-1 0 -46.2 kJ mol-1 O-59.7 kJ mol? A particular reaction has a standard molar...
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12. Calculate the standard reaction enthalpy for the reaction: N2H4(4) + H2(g) → 2NH3(g) Given: N2H4(4) + O2(g) → N2(g) + 2H2O(g) AH° = 0543 kJ 2H2(g) + O2(g) → 2H2O(g) AH° = 1484 kJ N2(g) + 3H2(g) + 2NH3(g) AH° = 092.2 kJ A. - 1119 kJ B. - 33 kJ C. -151 kJ D. + 151 kJ E. + 1119 kJ
Determine AH for the following reaction, 2NH3(g) + 5/20260) - 2NO(g) + 3H2019) given the thermochemical equations below. N2(g) + O2(0) - 2NO(g) N2(g) + 3H2(g) — 2NH3(0) 2H269) + O26) - 2H206) AH = +180.8 kJ AH = -91.8 kJ AH = -483.6 kJ -1178.2 kJ -452.8 kJ -394.6 kJ -211.0 kJ +1178.2 kJ
3. Use the thermochemical equations shown below to determine the enthalpy for the final reaction: N2(e) +202(g) → 2NOz (6) AH = ? Using (1) Nz (€) + 3H2(E) → 2NH3(g) AH = -92.2 kJ (2) 2NH, (g) + 4H20 (1) ► 2NO2 (g) + 7H2(g) AH = 1301.8 kJ (3) 2H20 (1) ► 2H2(g) + O2(g) AH = 571.6 kJ
3. (3 points) Hydrazine (N2H4) can react with oxyger in the following chemical reaction: NaH.(1 +0:0) - N2(g) + 2H20 (1) Calculate AH, for the reaction above, given the following data: 2NH3(g) + 3N20(g) - 4260) + 3H2000 AH,º=-1010. kJ/mol N20(g) + 3H2(g) → N2H (1) + H2O(1 AH-=-317 k!/inol 2NH3(g) + 40:09) - NzH4O + H20(1 AH,"=-143 kJ/mol H2(g) +4202(9) - H20(1) AH"=-286 kJ/mol
Determine the effect on the equilibrium for the reaction below when the pressure of NH3 is increased. N2(g) + 3 H2(g) = 2 NH3(g) AH = -91.8 kJ o a. The reaction will shift to the right. b. There will be no change. c. The reaction will shift to the left. Determine the effect on the equilibrium for the reaction below when the volume of the reaction vessel is increased. N2 (€) + 3H2(g) = 2 NH3(g) AH -91.8 kJ...