Question

us a very small pka. l that is less acidic than the compound from part a). NU hal isomer that has is more basic than the compound in part b). HO: Predict the structure of the product formed in the reaction of 3-(3-acetyl-5-formyl-4 hydroxyphenyl)propanoic acid with one equivalent of potassium hydroxide. Use curved arrows to indicate the direction of electron flow. To receive full credit, please draw the proper Lewis structure of the reagents and products. онс. соон 3-(3-acetyl-5-formyl-4-hydroxyphenylpropanoic acid 3. What reaction woul COCH indi

Answer 1

1. Since we know that the Potassium hydroxide is the base which abstract the most most acidic protons in the molecule.

2. we have the one equivalent of the potassium hydroxide, so it abstracts only one proton from the give compound.

3. The most acidic proton (hydrogen) in the given compound is the "CARBOXYLIC ACID GROUP".

4. So the one equivalent of KOH abstracts the proton from the most acidic proton from the carboxylic acid group. And gives the potassium salt of the corresponding compound.

5. If the presence of the excess KOH then the ALDOL CONDENSATION and CANIZARRO REACTION, mayt takes place.
LH H H [kt : 0-H ] 1 equivalent. -0. T осн. 3-(3-acetyl-5-formy 1-4-hydroxyphenyl, propanoic and I + H₂O I HI ok 20m CHE Potassium 3-63-acetyl-5-formyl-4-hydroxy phenyl) - propanoate,