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balance the following equation using the oxidation number method

Balance the following equation: 5. ClK2S O+ KOH KCIKSO4+H20
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Answer #1

5) Cl2 + K₂ S₂63 +KOH - KCl + K30+t20 6) 2 -2 -2+1 cl + K 20 tkou -1 +1 +6+2+1 -2 KCl + KyJoyt 120 - oxidation number! +2 oxivou! 0:X1=) R2 S203 + 2xox + 8%u* —> 242564 +86-4540 R!XQ> 4Cl2 + 8x84 togé-— Exel tgbu - add! K5303 +4Cl2 + 10 KOH + ~ 2x250

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