Question

Question 21 (4 points) Saved A sample of air has 3.55 moles of N2 and 2.50 moles of O2: What is the total pressure for the sample of air described above, if the volume is 29.51 L and the temperature is 300. Kelvin? O 5.06 atm 03.13 atm 01.01 atm 4.25 atm

Answer 1

We have, P V = n R T

where, P is a pressure of a gas, V is a volume of a gas, n is no. of moles of gas, R is a gas constant and T is temperature of gas.

$\therefore$ Partial pressure of N ₂ = n R T / V = 3.55 mol $\times$ 0.082057 L atm mol ^-1 K ^-1$\times$ 300 K / 29.51 L

Partial pressure of N ₂ = 2.96 atm

Similarly, Partial pressure of O ₂ = 2.50 mol $\times$ 0.082057 L atm mol ^-1 K ^-1$\times$ 300 K / 29.51 L

Partial pressure of O ₂ = 2.08 atm

Total pressure of sample of air = Partial pressure of N ₂ + Partial pressure of O ₂

= 2.96 atm + 2.08 atm

= 5.04 atm

ANSWER : 5.06 atm