The equivalent of an acid = molecular weight / number of H+ ions involved in the reaction.
Therefore, The equivalent H3PO4 if all 3 protons are titrated
= molecular weight / number of H+ ions involved in the reaction = 98/3 = 32.7 gm/mole
What is the equivalent weight of H3PO4 (MW 98 g/mol) if all 3 protons were titrated?...
Sodium hydroxide is standardized by a reaction with potassium hydrogen phtalate (KHP, MW 2042 g/mol). Calculate the molarity of a NaOH solution if 0.5123 g KHP were titrated to the equivalence point with 22.75 mL solution of NaOH. 0.0002509 moll Ob 0.02275 moll O c.0.1103 mol/l Od 1.10 mol/l
MW benzophenone: 182.217 g/mol
MW benzopinacolone: 348.45 g/mol
MW benzopinacol: 366.45 g/mol
MW isopropyl alcohol: 60.1 g/mol
I need help calculating the percent yield for both the
intermediate product and final product. All information that's
necessary for this to be done is present. chemical equation is
written in words
Data: Benzopinacolone (product): 25mg M.P.:184-187°C Benzopinacole (Intermediate Product): yout 85 mg M.P.:183-186 100mg of Benzoprenone mixed with ImL isopropy! alcond to synthesize Intermediate Product: 50 mg Intermediate product with glacial acetic...
How many moles of benzaldehyde (density d = 1.04 g/ml), (molecular weight mw = 106.12 g/mol) are required to react with 1.0 ml of acetone: (density d = 0.79 g/ml), (molecular weight mw = 58.08 g/mol)? 6. What is approximate theoretical yield for problem # 5 if you obtained 2.1 grams of dibenzylidene acetone (mw = 234.29 g/mol)?
8. If the reaction shown was carried out by allowing 7.50 mL of 2,2,3-trimethyl-3-pentano (MW=130.23 g/mol, d 0.857 g/mL) to react with catalytic acid to generate 3,4,4-trimethyl-2-pentene (MW=112.21 g/mol) and water, what is the theoretical yield (in grams) of the alkene product? (15 pts) OH H₂O H3PO4 + 4, 60 min 3,4,4-trimethyl-2-pentene 2,2,3-trimethyl-3-pentano 7. 50mL 15% 857 - 8.75 - 10 150.23 knool 112.215
5.8 g of
1,4-di-t-butyl-2,5-dimethoxynezene
(250.37 g/mol) were synthesized by reacting
10.5 mL of t-butyl alcohol (MW 74.12 g/mol, D
0.79 g/mL), 25 mL of concentrated sulfuric
acid (MW 98.08 g/mol, D 1.84
g/mL), and 5.9 g of 1,4-dimethoxybenzene (MW
138.17 g/mol) together. Calculate the percent
yield of this reaction.
Question 1 2 pts 5.8 g of 1,4-di-t-butyl-2,5-dimethoxynezene (250.373/mol) were synthesized by reacting 10.5 mL oft- butyl alcohol (MW 74.12 3/mol. D 0.795/mL), 25 mL of concentrated sulfuric acid (MW 98.08...
What weight of dry sodium acetate (FW = 82 g/mol) and volume of acetic acid (MW = 60 g/mol; density = 1.049 ml/g are required for 1 liter of 0.1 M sodium acetate, pH 4.50. (pKa= 4.73)? Answer: 3.6 mL acetic acid, 3.0 g sodium acetate Please provide steps to get the above answer.
A sample containing a mixture of SrCl2·6H2O (MW = 266.62 g/mol) and CsCl (MW = 168.36 g/mol) originally weighs 1.9715 g. Upon heating the sample to 320 °C, the waters of hydration are driven off SrCl2·6H2O, leaving the anhydrous SrCl2. After cooling the sample in a desiccator, it has a mass of 1.6811 g. Calculate the weight percent of Sr, Cs, and Cl in the original sample. 1) wt% Sr 2) wt% Cs 3) wt% Cl
5.1 g of
1,4-di-t-butyl-2,5-dimethoxynezene
(250.37 g/mol) were synthesized by reacting
9.7 mL of t-butyl alcohol (MW 74.12 g/mol, D
0.79 g/mL), 25 mL of concentrated sulfuric
acid (MW 98.08 g/mol, D 1.84
g/mL), and 4.2 g of 1,4-dimethoxybenzene (MW
138.17 g/mol) together. Calculate the percent
yield of this reaction. Write your answer without a percent
sign and to 2 decimal places. MW=molecular weight, D=density of
liquid. PLEASE SHOW WORK
OH t-butanol 1,4-di-tert-butyl-2,5-dimethoxybenzene 1,4-dimethoxybenzene
3. What is the molarity of a solution that contains 17 g of HI (MW=128 g-mol-') in 0.50 L of solution? A 0.94 B 0.42 C 1.0 D 2.0 E 0.26
A 1.18 M solution of citric acid (H3C6H507, MW=192.122 g/mol) in water has a density of 1.8 g/mL. What is the mass percent of this solution? Select one: a. 75.42% O b. None of the choices is correct c. 3.93% Od. 12.59 % O e. 68.21 %