Question

how do i determine #2 (of A and B) from a graph with these points on the second photo.

Date REPORT SHEET Heat of Neutralization A. Heat Capacity of Calorimeter 29 O 1. Temp. of calorimeter and water before mixing 2. Temp. of warm water 3a O °C 3. Maximum temp. determined from your curve °C 4. Heat lost by warm water (temp decrease x 50.0 gx 4.184 J/K-g) = 1443.481 5. Heat gained by cooler water (temp. increase x 50.0 gx 4.184 J/K-g) 1642 22 6. Heat gained by the calorimeter [(4) - (5)] L98 74J 7. Heat capacity of calorimeter: | ৭९. 4 heat gained by the calorimeter temperature increase 25.317 JK 7.89 B. Heat of Neutralization of HCI-NaOH 1. Temp. of calorimeter and NaOH ZeeZu.ot Temp. of HCI 2. AT determined from your curve after adding HCI to the NaOH °C 3. Heat gained by solution (temperature increasex 100 gx 4.184 J/K-g) 30 x 4.t84 4. Heat gained by calorimeter (Temperature increase x heat capacity of calorimeter) ToS.92J 2SiO 4x 2S .317 26l6.32 5. Total joules released by reaction [(3) + (4)]

sorry i meant to say #3 for part A and #2 for part B.

Answer 1

A-3) It is read in curve A, the last temperature at which the solution is, is 31 ° C.

B-2) The last temperature of curve B (30 ° C) is read and the ΔT is calculated:

ΔT = 30 - 24 = 6 ° C

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