Question

Preparing Dilute Solutions C1 V1 C2 V2 C1 is the concentration of the original concentrated solution V1 is the volume of the1. Starting with 0.1250 M Cu (NH3)2* as the stock (concentrated) solution, calculate the concentrations of each of the follow

0 0
Add a comment Improve this question Transcribed image text
Answer #1

t. @ We know, av,=C2 V2 Anne Now, Q = 0.1250CM), V; = 15.0mb vz = 20.0mb i C2 = GV = L0-1250x 15.0 * 15:0).(M)=0.09375(M) 20.

Add a comment
Know the answer?
Add Answer to:
Preparing Dilute Solutions C1 V1 C2 V2 C1 is the concentration of the original concentrated solution...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • LUIGIO ASSICUL Name CHEM 1090-General Chemistry Section Preparing Dilute Solutions C. V, - CV C is...

    LUIGIO ASSICUL Name CHEM 1090-General Chemistry Section Preparing Dilute Solutions C. V, - CV C is the concentration of the original concentrated solution V1 is the volume of the original concentrated solution C is the concentration of the final dilute solution V2 is the volume of the final dilute solution Solution unit is mol/l which can also be written as M A solution that is 0.1 MNaonds A common solution unit is mol/l 0.1 moles NaOH for every liter of...

  • 1. 2. Using the equation C1V1 = C2V2, calculate the volume (V1) of concentrated solution and...

    1. 2. Using the equation C1V1 = C2V2, calculate the volume (V1) of concentrated solution and the volume of water needed to dilute the following solutions: Concentration Volume (in mls) Concentration of Volume (in mls) of Volume (in mls) of diluted of desired available stock stock solution required of solvent solution desired solution (V2) solution (C1) to make the diluted required to (C2) solution (V1) achieve desired volume (V2-V1) 5 mg/ml 100 ml 1000 mg/ml 15% 10 ml 50% 0.250...

  • The concentration of a solution after dilution can be found by: where M1 is the concentrated...

    The concentration of a solution after dilution can be found by: where M1 is the concentrated solution (in this lab, 0.400 M), and V1 is the volume of the concentrated solution placed in the test tube. The V2 is the total volume of concentrated solution plus water added, and M2 is the concentration of the solution after diluting. Tube 1 has 2.00 mL of the 0.400 M Ni2+ solution and 8.00 mL of water added. What is the concentration of...

  • You have been given a jar of red fruit punch and been asked to determine the...

    You have been given a jar of red fruit punch and been asked to determine the concentration of red dye in the fruit punch. You obtain a stock solution of this red dye and it has a concentration of 0.00485 M (in the lab room, the stock solution is found in the hood). You take 10.0 mL of this stock solution and dilute it to 100.0 mL. You call this your standard solution. Usinga colorimeter, you determine that the red...

  • You have been given a jar of red fruit punch and been asked to determine the...

    You have been given a jar of red fruit punch and been asked to determine the concentration of red dye in the fruit punch. You obtain a stock solution of this red dye and it has a concentration of 0.00243 M (in the lab room, the stock solution is found in the hood). You take 10.0 mL of this stock solution and dilute it to 100.0 mL. You call this your standard solution. Using a colorimeter, you determine that the...

  • To construct a calibration curve we would need to take our stock solution and dilute it...

    To construct a calibration curve we would need to take our stock solution and dilute it to different concentrations. We would then test those different concentration in our spectrophotometer to test their absorbance. If we diluted our samples as follows, calculate the resulting concentrations. (HINT: this is dilution which means we can use M1V1=M2V2, where M1 is our original 150 mM concentration, V1 is the volume of the original concentration that we added water to dilute, M2 is the concentration...

  • Dilution is a process in which the concentration of a solution is lowered by adding more...

    Dilution is a process in which the concentration of a solution is lowered by adding more solvent. Some of the reasons dilutions are performed are to minimize measurement errors when preparing a series of solutions at different concentrations, to save time and laboratory space, and to make more accurate measurements on an analytical balance when the target concentration is very low. The new concentration of a diluted solution can be determined from the following equation, sometimes called the dilution equation,...

  • Laboratory goggles must be worn! A) Preparation of Solutions from Concentrated Solution In this part the...

    Laboratory goggles must be worn! A) Preparation of Solutions from Concentrated Solution In this part the experiment you will prepare several dilute solutions from the more concentrated cobalt nitrate solution 1. Read the label on the provided cobalt nitrate solution and record the molarity accurately. su-olu 563/ 316.603:48 صلاح 2. 3. 4. Molarity of Ca(NO3)2 solution 182.95 g/mol Obtain a 25-ml buret. Examine its markings, the line that spans the entire circumference occur for each milliliter. The smaller lines indicate...

  • The initial concentration of hydrochloric acid, HCl, is 12 M. I want to dilute this solution...

    The initial concentration of hydrochloric acid, HCl, is 12 M. I want to dilute this solution to get 500. 5. 0 mL of a 1.5 M solution. How many mL of the concentrated HCI must I use? 6. How many moles of sodium carbonate are contained in 200.00 mL of an 0.835 M solution of Na2CO3? 7. For the following reaction: 3 Cu(o+ 4 HNOs (a)3 Cu(NO,)2 (0)+2 NO20)+2 H20 What volume of 0.285 M HNOs is required for complete...

  • A Cu(II) Standard solution has been diluted as following table concentration and react with NH3 solution...

    A Cu(II) Standard solution has been diluted as following table concentration and react with NH3 solution to form a colored complex as Cu(NH3)Cl2. Each of the standard has been measured the % Transmission in a 1.00 cm cell at 590 nm : Concentration of Cu(II) in ppm % T A510 10 63.1 20 47.9 30 37.2 40 30.9 50 25.7 60 19.5 70 31.6 80 12.0 a. You took a Copper wire sample, weight 1 gram and dissolved to 1...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT