Question

The concentration of a solution after dilution can be found by:

where M₁ is the concentrated solution (in this lab, 0.400 M), and V₁ is the volume of the concentrated solution placed in the test tube. The V₂ is the total volume of concentrated solution plus water added, and M₂ is the concentration of the solution after diluting.

Tube 1 has 2.00 mL of the 0.400 M Ni²⁺ solution and 8.00 mL of water added. What is the concentration of the diluted solution?

Answer 1

M in mol/litre , V in milli litre, so M xV = millimoles of a substance, which does not change on dilution

Since, Tube 1 has 2.00 mL of the 0.400 M Ni2+ solution,

V1 = 2.00 mL,           M1 = 0.400 M

V2 = (2.00 + 8.00) ml = 10.00 ml;   and M2 = ?

Note that total volume will be volume of cocentrated solution taken + the volume of water added.

Now,   M1V1       =           M2 V2 ; putting values

$\Rightarrow$    (0.400 M) x 2.00 mL = M2 x 10.00 ml

$\Rightarrow$     M2 =   0.0800 M              .....up to 3 significant digits

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