The statistic software output for this problem is:
The 98% CI is :
-5.97 11.97
The information below is based on independent random samples taken from two normally distributed populations having...
The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 90% confidence interval estimate for the difference between the two population means. n1 = 17 x1 44 n2 13 x2 = 49 The 90% confidence interval is s(uI-12) (Round to two decimal places as needed.) «D
The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 95% confidence interval estimate for the difference between the two population means. n1 14 x145 n2 13 2 47 The 95% confidence interval is s (μ1-12) s Round to two decimal places as needed)
(11-13] The information below is based on independent simple random samples taken from two normally distributed populations having equal variances. Based on the sample information, answer the following questions about the difference between two population means. ni = 13 n2 = 12 X 1 = 51 i , = 58 S = 6 S2 = 5 11) (1 point) The parameter of interest could be: a. X1-X2 b. H1-42 C. P1-P2 d. Other, please specify: 12) (1 point) Your friend...
The following results are for independent random samples taken from two populations. Sample 1 Sample 2 n1 = 20 n2 = 30 x1 = 22.9 x2 = 20.1 s1 = 2.6 s2 = 4.8 (c) At 95% confidence, what is the margin of error? (Round your answer to one decimal place.) ? (d) What is the 95% confidence interval for the difference between the two population means? (Use x1 − x2. Round your answers to one decimal place.) ? to...
Independent random sampling from two normally distributed populations gives the results below. Find a 99% confidence interval estimate of the difference between the means of the two populations ni 70 X1-377 ƠI :19 n2-34 x2 334 ơ2-29 The confidence interval is < (m-μ2) (Round to four decimal places as needed)
Consider the following results for independent random samples taken from two populations. Sample 1 Sample 2 n1= 20 n2 = 40 x1= 22.1 x2= 20.6 s1= 2.9 s2 = 4.3 a. What is the point estimate of the difference between the two population means (to 1 decimal)? b. What is the degrees of freedom for the t distribution (round down)? c. At 95% confidence, what is the margin of error (to 1 decimal)? d. What is the 95% confidence interval...
are my answers correct? Consider the following data from two independent samples with equal population variances. Construct a 99% confidence interval to estimate the difference in population means. Assume the population variances are equal and that the populations are normally distributed x1 = 67.9 s1 = 12.8 n1 = 10 X2 74.8 s2 = 8.1 n2 = 14 Click here to see the t-distribution table, page 1 Click here to see the t-distribution table,_page 2 The 99% confidence interval is...
Two random samples are selected from two independent populations. A summary of the samples sizes, sample means, and sample standard deviations is given below: n1=51, n2=46, x¯1=57.8, x¯2=75.3, s1=5.2 s2=11 Find a 94.5% confidence interval for the difference μ1−μ2μ1−μ2 of the means, assuming equal population variances. Confidence Interval =
the following results for independent random samples taken from two populations. Sample 1 Sample 2 n1-10 n2-30 x1-22.5 x2 20.6 S1-2.5 S2 4.9 a, What is the point estimate of the difference between the two population means (to 1 decimal)? b. What is the degrees of freedom for the t distribution (round down your answer to nearest whole number)? c. At 95% confidence, what is the margin of error (to 1 decimal)? d. What is the 95% confidence interval for...
Independent random sampling from two normally distributed populations gives the results below. Find a 95% confidence interval estimate of the difference between the means of the two populations. ng = 88 n2 = 80 = 123 x2 = 121 01 = 22 02 = 11 The confidence interval is <(H1-H2) (Round to four decimal places as needed)