SE = sqrt(22^2/88 + 11^2/80)
SE = 2.6481
Given CI level is 95%, hence α = 1 - 0.95 = 0.05
α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96
CI = (x1bar - x2bar - Zc * sE , x1bar - x2bar + Zc * SE)
CI = (2 - 1.96 * 2.6481 , 2 + 1.96 * 2.6481)
CI = (-3.1903 , 7.1903)
Independent random sampling from two normally distributed populations gives the results below. Find a 95% confidence...
Independent random sampling from two normally distributed populations gives the results below. Find a 99% confidence interval estimate of the difference between the means of the two populations ni 70 X1-377 ƠI :19 n2-34 x2 334 ơ2-29 The confidence interval is < (m-μ2) (Round to four decimal places as needed)
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The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 95% confidence interval estimate for the difference between the two population means. n1 14 x145 n2 13 2 47 The 95% confidence interval is s (μ1-12) s Round to two decimal places as needed)
The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 90% confidence interval estimate for the difference between the two population means. n1 = 17 x1 44 n2 13 x2 = 49 The 90% confidence interval is s(uI-12) (Round to two decimal places as needed.) «D
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Check My Work Video Consider the following results for two independent random samples taken from two populations Sample 1 Sample 2 1 40 X1 13. X2 - 11.6 01 = 2.3 a. What is the point estimate of the difference between the two population means? (to 1 decimal) n2=30 02-3.1 1.5 b, provide a 90% confidence interval for the difference between the two population means (to 2 decimals. Use z-table. 89 c, provide a 95% confidence interval for the difference...
Consider the following results for independent random samples taken from two populations. Sample 1 Sample 2 n1= 20 n2 = 40 x1= 22.1 x2= 20.6 s1= 2.9 s2 = 4.3 a. What is the point estimate of the difference between the two population means (to 1 decimal)? b. What is the degrees of freedom for the t distribution (round down)? c. At 95% confidence, what is the margin of error (to 1 decimal)? d. What is the 95% confidence interval...
Exercise 10.9(Algorithmic)) Consider the following results for independent random samples taken from two populations Sample 1 Sample 2 n1 10 n2 30 x1- 22.8 x2 20.9 $1-2.9 s2 4.8 a. What is the point estimate of the difference between the two population means (to 1 decimal)? b. What is the degrees of freedom for the t distribution (round down)? C. At 95% confidence, what is the margin of error (to 1 decimal)? d. what is the 95% confidence interval for...
The following results are for independent random samples taken from two populations. Sample 1 Sample 2 n1 = 20 n2 = 30 x1 = 22.9 x2 = 20.1 s1 = 2.6 s2 = 4.8 (c) At 95% confidence, what is the margin of error? (Round your answer to one decimal place.) ? (d) What is the 95% confidence interval for the difference between the two population means? (Use x1 − x2. Round your answers to one decimal place.) ? to...