Independent random sampling from two normally distributed populations gives the results below. Find a 90% confidence interval estimate of the difference between the means of the two populations.
nx = 81 x̄ = 113 σx = 21
ny = 80 ȳ = 111 σy = 12
The confidence interval is____________ < μx − μy < _________________
(Round to four decimal places as needed)
Independent random sampling from two normally distributed populations gives the results below. Find a 90% confidence...
independent random sampling from two normally distributed populations gives the results below. Find a 99% confidence interval estimate of the difference between the means of the two populations. nx = 90 ny = 83 x=115 σχ = 23 9,-23 ơy-10 у = 107 The confidence interval is
Independent random sampling from two normally distributed populations gives the results below. Find a 99% confidence interval estimate of the difference between the means of the two populations ni 70 X1-377 ƠI :19 n2-34 x2 334 ơ2-29 The confidence interval is < (m-μ2) (Round to four decimal places as needed)
Independent random sampling from two normally distributed populations gives the results below. Find a 95% confidence interval estimate of the difference between the means of the two populations. ng = 88 n2 = 80 = 123 x2 = 121 01 = 22 02 = 11 The confidence interval is <(H1-H2) (Round to four decimal places as needed)
The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 90% confidence interval estimate for the difference between the two population means. n1 = 17 x1 44 n2 13 x2 = 49 The 90% confidence interval is s(uI-12) (Round to two decimal places as needed.) «D
The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 95% confidence interval estimate for the difference between the two population means. n1 14 x145 n2 13 2 47 The 95% confidence interval is s (μ1-12) s Round to two decimal places as needed)
The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 98% confidence interval estimate for the difference between the two population means. n = 12 X1 = 57 S1 = 9 n2 = 11 X2 = 54 S2 = 8 The 98% confidence interval is $(11-12) (Round to two decimal places as needed.)
Consider the following results for two independent random samples taken from two populations. Sample 1 Sample 2 n 1 = 40 n 2 = 35 x 1 = 13.8 x 2 = 11.3 σ 1 = 2.5 σ 2 = 3 What is the point estimate of the difference between the two population means? (to 1 decimal) Provide a 90% confidence interval for the difference between the two population means (to 2 decimals). Use z-table. ( , ) Provide a...
Given two independent random samples with the following results: ni = 15 n2 = 13 Xi = 153 X2 = 114 $i = 19 S2 = 21 Use this data to find the 95 % confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed. Copy Data Step 1 of 3: Find the critical value that should be used in constructing the confidence interval. Round...
15 Correct Given two independent random samples with the following results: n = 13 = 142 12 = 165 $ = 13 Use this data to find the 98% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed Copy Data Step 1 of 3 : Find the point estimate that should be used in constructing the confidence interval. Answer How to enter your answer...
If we are testing the difference between the means of two normally distributed independent populations with samples of n1 = 10, n2 = 11, the degrees of freedom for the t statistic is ______. 19 9 8 18