are my answers correct? Consider the following data from two independent samples with equal population variances....
Consider the following data from two independent samples with equal population variances. Construct a 99% confidence interval to estimate the difference in population means. Assume the population variances are equal and that the populations are normally distributed. x overbar 1 equals= 37.1 x overbar 2 equals= 32.8 s 1 equals= 8.68 S2 equals= 9.59 N1 equals= 15 N2 equals= 16 The 99% confidence interval is ( )(. ).
cnsider the following data rom wo populations are normally distributed. dependent samples th equal population var ances on struct a 9 % con der ce te val o es mate he dif rn ein po ulation means. Assume the popula on variances are equal and at the X1-36.42 S1-8.8 n1 #18 82 9.1 n2 19 ge 1 Click here to see the t distribution table page 2 The 90% confidence interval is( Round to two decimal places as needed.) DD
onsider the following data rom t o independent samples h equal population variances onstruct a 98% con ce interval to estimate the difference in population means ss me he population variances are equal and that the populations x137.1 S1 = 8.8 s2 = 9.2 The 98% confidence interval is (Round to two decimal places as needed.)
Suppose we had the following summary statistics from two different, independent populations, both with variances equal to σ. Population 1: ¯x1= 126, s1= 8.062, n1= 5 Population 2: ¯x2= 162.75, s2 = 3.5, n2 = 4 We want to find a 99% confidence interval for μ2−μ1. To do this, answer the below questions. Suppose we had the following summary statistics from two different, independent populations, both with variances equal to o: 1. Population 1: Ti = 126, $i = 8.062,...
Two random samples are selected from two independent populations. A summary of the samples sizes, sample means, and sample standard deviations is given below: n1=51, n2=46, x¯1=57.8, x¯2=75.3, s1=5.2 s2=11 Find a 94.5% confidence interval for the difference μ1−μ2μ1−μ2 of the means, assuming equal population variances. Confidence Interval =
Two random samples are selected from two independent populations. A summary of the samples sizes, sample means, and sample standard deviations is given below: n1= 37 n2=44 x-bar1= 58.6 x-bar2= 73.8 s1=5.4 s2=10.6 Find a 97% confidence interval for the difference μ1−μ2μ1−μ2 of the means, assuming equal population variances.
Consider the following results for independent random samples taken from two populations. Sample 1 Sample 2 n1= 20 n2 = 40 x1= 22.1 x2= 20.6 s1= 2.9 s2 = 4.3 a. What is the point estimate of the difference between the two population means (to 1 decimal)? b. What is the degrees of freedom for the t distribution (round down)? c. At 95% confidence, what is the margin of error (to 1 decimal)? d. What is the 95% confidence interval...
Independent random samples selected from two normal populations produced the sample means and standard deviations shown to the right. a) Assuming equal variances, conduct the test Ho: (u1-u2)=0 against Ha: (u1-u2)=/=0 using a=0.05 b) Find and interpret the 95% confidence interval for (u1-u2) Sample1: n1=17, x1=5.9, s1=3.8 Sample2: n2=10, x1=7.3, s2=4.8
the following results for independent random samples taken from two populations. Sample 1 Sample 2 n1-10 n2-30 x1-22.5 x2 20.6 S1-2.5 S2 4.9 a, What is the point estimate of the difference between the two population means (to 1 decimal)? b. What is the degrees of freedom for the t distribution (round down your answer to nearest whole number)? c. At 95% confidence, what is the margin of error (to 1 decimal)? d. What is the 95% confidence interval for...
The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 98% confidence interval estimate for the difference between the two population means. n = 12 X1 = 57 S1 = 9 n2 = 11 X2 = 54 S2 = 8 The 98% confidence interval is $(11-12) (Round to two decimal places as needed.)