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onsider the following data rom t o independent samples h equal population variances onstruct a 98%...
cnsider the following data rom wo populations are normally distributed. dependent samples th equal population var...
cnsider the following data rom wo populations are normally distributed. dependent samples th equal population var ances on struct a 9 % con der ce te val o es mate he dif rn ein po ulation means. Assume the popula on variances are equal and at the X1-36.42 S1-8.8 n1 #18 82 9.1 n2 19 ge 1 Click here to see the t distribution table page 2 The 90% confidence interval is( Round to two decimal places as needed.) DD
are my answers correct? Consider the following data from two independent samples with equal population variances....
are my answers
correct?
Consider the following data from two independent samples with equal population variances. Construct a 99% confidence interval to estimate the difference in population means. Assume the population variances are equal and that the populations are normally distributed x1 = 67.9 s1 = 12.8 n1 = 10 X2 74.8 s2 = 8.1 n2 = 14 Click here to see the t-distribution table, page 1 Click here to see the t-distribution table,_page 2 The 99% confidence interval is...
Consider the following data from two independent samples with equal population variances. Construct a 99% confidence...
Consider the following data from two independent samples with equal population variances. Construct a 99% confidence interval to estimate the difference in population means. Assume the population variances are equal and that the populations are normally distributed. x overbar 1 equals= 37.1 x overbar 2 equals= 32.8 s 1 equals= 8.68 S2 equals= 9.59 N1 equals= 15 N2 equals= 16 The 99% confidence interval is ( )(. ).
The information below is based on independent random samples taken from two normally distributed populations having...
The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 98% confidence interval estimate for the difference between the two population means. n = 12 X1 = 57 S1 = 9 n2 = 11 X2 = 54 S2 = 8 The 98% confidence interval is $(11-12) (Round to two decimal places as needed.)
Two random samples are selected from two independent populations. A summary of the samples sizes, sample...
Two random samples are selected from two independent populations. A summary of the samples sizes, sample means, and sample standard deviations is given below: n1=51, n2=46, x¯1=57.8, x¯2=75.3, s1=5.2 s2=11 Find a 94.5% confidence interval for the difference μ1−μ2μ1−μ2 of the means, assuming equal population variances. Confidence Interval =
Two random samples are selected from two independent populations. A summary of the samples sizes, sample...
Two random samples are selected from two independent populations. A summary of the samples sizes, sample means, and sample standard deviations is given below: n1= 37 n2=44 x-bar1= 58.6 x-bar2= 73.8 s1=5.4 s2=10.6 Find a 97% confidence interval for the difference μ1−μ2μ1−μ2 of the means, assuming equal population variances.
15 Correct Given two independent random samples with the following results: n = 13 = 142...
15 Correct Given two independent random samples with the following results: n = 13 = 142 12 = 165 $ = 13 Use this data to find the 98% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed Copy Data Step 1 of 3 : Find the point estimate that should be used in constructing the confidence interval. Answer How to enter your answer...
onsider the following results for independent samples taken from two populations. Sample 1 Sample 2 n1...
onsider the following results for independent samples taken from two populations. Sample 1 Sample 2 n1 = 500 n2= 300 p1= 0.48 p2= 0.31 a. What is the point estimate of the difference between the two population proportions (to 2 decimals)? b. Develop a 90% confidence interval for the difference between the two population proportions (to 4 decimals). Use z-table. to c. Develop a 95% confidence interval for the difference between the two population proportions (to 4 decimals). Use z-table....
Given two independent random samples with the following results: n1=8 x‾1=166 s1=28 n2=12 x‾2=194 s2=25 Use...
Given two independent random samples with the following results: n1=8 x‾1=166 s1=28 n2=12 x‾2=194 s2=25 Use this data to find the 90% confidence interval for the true difference between the population means. Assume that the population variances are not equal and that the two populations are normally distributed. Copy Data Step 2 of 3 : Find the margin of error to be used in constructing the confidence interval. Round your answer to six decimal places.
The information below is based on independent random samples taken from two normally distributed populations having...
The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 95% confidence interval estimate for the difference between the two population means. n1 14 x145 n2 13 2 47 The 95% confidence interval is s (μ1-12) s Round to two decimal places as needed)
cnsider the following data rom wo populations are normally distributed. dependent samples th equal population var ances on struct a 9 % con der ce te val o es mate he dif rn ein po ulation means. Assume the popula on variances are equal and at the X1-36.42 S1-8.8 n1 #18 82 9.1 n2 19 ge 1 Click here to see the t distribution table page 2 The 90% confidence interval is( Round to two decimal places as needed.) DD
are my answers
correct?
Consider the following data from two independent samples with equal population variances. Construct a 99% confidence interval to estimate the difference in population means. Assume the population variances are equal and that the populations are normally distributed x1 = 67.9 s1 = 12.8 n1 = 10 X2 74.8 s2 = 8.1 n2 = 14 Click here to see the t-distribution table, page 1 Click here to see the t-distribution table,_page 2 The 99% confidence interval is...
The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 98% confidence interval estimate for the difference between the two population means. n = 12 X1 = 57 S1 = 9 n2 = 11 X2 = 54 S2 = 8 The 98% confidence interval is $(11-12) (Round to two decimal places as needed.)
15 Correct Given two independent random samples with the following results: n = 13 = 142 12 = 165 $ = 13 Use this data to find the 98% confidence interval for the true difference between the population means. Assume that the population variances are equal and that the two populations are normally distributed Copy Data Step 1 of 3 : Find the point estimate that should be used in constructing the confidence interval. Answer How to enter your answer...
The information below is based on independent random samples taken from two normally distributed populations having equal variances. Based on the sample information, determine the 95% confidence interval estimate for the difference between the two population means. n1 14 x145 n2 13 2 47 The 95% confidence interval is s (μ1-12) s Round to two decimal places as needed)
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