Question

Pre-lab Assignment: On Separate sheet (to turn in) 1. A compound with molecular formula CsH10Br2 displays the following 13C NMR along with the DEPT-90 and DEPT-135 13CNMR spectra. What is the structure for this compound? DEPT-90 DEPT-135 Broadband decoupled 5 ppm 10 15 25 30 35 45 50 55 60 65 70 75 -20 -40

Answer 1

a W Molecular formula – C5H1oBr2 sptes of unsaturatson sites of unsaturation = 20ct)-H -Br - 215+1-10-2 = 12-10-2 sites of unsaturation = 0 Indicates No double bond. The Dept spectroscopy as used to distinguish CH3, 42 and - CH gooup. It peak pp pept es up heare positive peak indicates CH₃ group If peak En Dept is down bence negative peak the footer CH1 CH₂ group Ir uppoak / positive peak - poton peak | Megaliye pouk CBR klith DEPT-135 To The negative peak in DEPT-135 at 27 ppm andicates CH₂ CH - 1 The negative peak at 32 ppm andscates CH2 ICH ly the negative peak at 34 ppon Indicates CHICH : The probable spucture i 32 32ppm 34 27 34 ppm

a W Molecular formula – C5H1oBr2 sptes of unsaturatson sites of unsaturation = 20ct)-H -Br - 215+1-10-2 = 12-10-2 sites of unsaturation = 0 Indicates No double bond. The Dept spectroscopy as used to distinguish CH3, 42 and - CH gooup. It peak pp pept es up heare positive peak indicates CH₃ group If peak En Dept is down bence negative peak the footer CH1 CH₂ group Ir uppoak / positive peak - poton peak | Megaliye pouk CBR klith DEPT-135 To The negative peak in DEPT-135 at 27 ppm andicates CH₂ CH - 1 The negative peak at 32 ppm andscates CH2 ICH ly the negative peak at 34 ppon Indicates CHICH : The probable spucture i 32 32ppm 34 27 34 ppm