Question

20. A compound with the formula C5H100 exhibits the following C NMR signals Broadband decoupled: 207, 45, 28, 16, and 12 ppm

Need help proposing a structure given the following data. Thank you.

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Answer #1

NOTE

DEPT-90 only shows CH, and DEPT-135 shows CH/CH3 with a positive phase and CH2 with a negative one.

ANSWER EXPLANATION

207 peak can be for either aldehyde or ketone.

As DEPT 90 shown no peak the compound can't be aldehyde. So, the compound is ketone.

Two negative peak for DEPT-135 indicates two CH2 groups are present.

Two positive peak indicates two CH3 groups are present.

The following structure is proposed.

HC- &- CH₂ - CH2-Cty sa b e de - Eg Hoo 5 peaks in Benmr a 28 ppm, b> 207ppm е - 45 ) 416 ppm ex 12ppm

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