Question

15. Determine the degrees of unsaturation and then propose a structure for a compound, CaHoO with the following 1C NMR spectra data: (5 points) . Broadband decoupled 1BC NMR: 19.0, 31.7, and 69.5 6 DEPT-90: 31.7 δ -C DEPT-135: positive peak at 19.0 and a negative peak at 69.56.C A .

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Answer #1

NMR structural analysis

15.

Formula = C4H10O

Degree of unsaturation = 0

13C NMR showed,

19 ppm for the two CH3 carbons

31.7 ppm for CH carbon

69.5 ppm for CH2 carbon next to oxygen

Dept-90 : showed one peak at 31.7 ppm for CH carbon

Dept-135 : showed two peaks, 19 ppm +ve for CH3 carbons and 69.5 ppm as -ve peak for CH2 carbon

Possible structure of compound,

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