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A coin is tossed and has three possible outcomes: Head, Tail, Edge. Suppose P(Head) = 1/3,...

A coin is tossed and has three possible outcomes: Head, Tail, Edge. Suppose
P(Head) = 1/3, P(T ail) = 1/2, P(Edge) = 1/6. The coin is repeatedly tossed. If the trials are identical
and independent, what is the probability of getting a head before getting a tail?

math   Statistics-And-Probability   
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Answer #1

The trials are identical and independent.

So the probability of head, tail and edge will not change.

P(Getting a head before getting a tail) = P(Head) = 1/3

Which is same for all trials since the trials are independent.

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