Firstly try to balance N on both sides as follows:
Cu + 3HNO3 ---> Cu(NO3)2 + H2O + NO
Since hydrogen is unbalanced try to balance hydrogen then
Cu + 4HNO3 ---> Cu(NO3)2 + 2H2O + NO
Again N atom is unbalanced try to balance it:
Cu + 4HNO3 ---> Cu(NO3)2 + 2H2O + 2 NO
now oxygen is unbalanced try to balance it again
Cu + 4HNO3 ---> Cu(NO3)2 + 4 H2O + 2 NO
Oxygen is balanced now but hydrogen seems to be unbalanced try that again:
Cu + 8 HNO3 ---> Cu(NO3)2 + 4 H2O + 2 NO
now nitrogen is balanced it can be done by following way:
Cu + 8 HNO3 ---> 3 Cu(NO3)2 + 4 H2O + 2 NO
Except copper everything is balanced
3 Cu + 8 HNO3 ---> 3 Cu(NO3)2 + 4 H2O + 2 NO
Reaction is balanced now !
Balance the following equation: . V + HNO3 -----> V(NO3)3 + N2O + H2O
Balance the following equation: V + HNO3 -----> V(NO3)3 + N2O + H2O
balance redox equation number 7 and 11 Cu(s) + - HNO3(aq) => Cu(NO3)2(aq) + _NO2(0) (conc, acid) Write balanced equation: 11. V + Clos (aq) => HV20, (ma) + - Cha) (basic soln.) Write balanced equation:
Balance the equation for the reaction observed: _ Cu(s) + HNO3(aq) → Cu(NO3)2(aq) +_ NO2(g) + H2O(1) 3. Add 40 mL of 3.0 M NaOH (sodium hydroxide) to the solution in your beaker. Write the balanced equation for the reaction observed: 4. Add 2-3 boiling chips to your beaker and carefully heat the solution, while stirring with a stirring rod, just to the boiling point. (Do NOT boil. Have a low flame and keep the beaker well above the flame.)...
1. Balance the three copper reactions: +H20 (1) +NO2 (g) Cu(NO3)2 (aq) i) Cu (s) HNO3 (aq) NANO3 (aq) NaOH (aq) Cu(OH)2 (s) + ii) Cu(NOs)2 (aq) + H2O (1I) CuO (s) iii) Cu(OH)2 (s) 2. In reaction (i), suppose you add 4.0 mL of 6M nitric acid to a sphere of copper metal that weighs 0.65 grams. Which reactant is the limiting reagent? (Show your work)
Balance the following chemical equation? Ca(OH)2(aq)+HNO3(aq)→H2O(l)+Ca(NO3)2(aq) Express your answer as a chemical equation. Identify all of the phases in your answer?
need help balancing the 1st equation then name what type of reaction is occurring for each equation A HNO3(aq) + Cu(s) + O2(g) - Cu(NO3)2(aq) + 4H2O(l) +BANO2(g) Cu(NO3)2(aq) + 2 NaOH(aq) - Cu(OH)2(s) +2 NaNO3(aq) rxn. 2 Cu(OH)2(s) - CuO(s) + H2O(l) rxn. 3 rxn. 4 Cuo(s) + H2SO4(aq) CuSO.(aq) + Zn(s) — CuSO4(aq) + H2O(l) + ZnSO4(aq) + Cu(s) rxn. 5
Copper reacts with nitric acid via the following equation: 3 Cu(s) + 8 HNO3(aq) → 3 Cu(NO3)2(aq) + 2 NO(g) + 4 H2O(ℓ) What mass of NO(g) can be formed when 20.7 g of Cu reacts with 50.0 g HNO3? g NO
1. Balance the three copper reactions: + H20 (1) Cu(NO3)2 (aq) + NO2(g) i) Cu (s) + HNO3 (aq) ii) Cu(NO3)2 (aq) + NaOH(aq) Cu(OH)2 (s) + NaNO3(aq) (aq) - iii) Cu(OH)2 (S) Cuo(s) + H2O (1) 2. In reaction (i), suppose you add 4.0 mL of 6 M nitric acid to a sphere of copper metal that weighs 0.65 grams. Which reactant is the limiting reagent? (Show your work)
6a. Balance the equation: HNO3 (aq) + Ba(OH)2 (aq)--> -H2O() + Ba(NO3)2 (aq) 6b. If 0.295 moles of Ba(OH)2 are used, how many moles of Ba(NO)2 will be produced ? 6c. If 0.295 moles of Ba(OH)2 are used, how many grams of Ba(NO,)2 will be produced ? 6d. If 0.295 moles of HNO, are used, how many grams of H,0 can be produced?