please answer both questions QUESTION 16 A student measured the pH of a 0.15 M solution...
A 0.30 M solution of an acid with KA= 3.0 x 10-7 is titrated with a 0.15 M solution of sodium hydroxide. Calculate the pH of the solution after 110 mL of the sodium hydroxide solution is added to 55 mL of the acid solution.
A 0.30 M solution of an acid with KA = 3.0 x 10-7 is titrated with a 0.15 M solution of sodium hydroxide. Calculate the pH of the solution after 110 mL of the sodium hydroxide solution is added to 55 mL of the acid solution.
Consider a titration of 25.00 mL Chloroacetic Acid solution [ka=1.4x10^-3] with 0.1202 M solution of sodium hydroxide. The volume of 27.40 mL of NaOH(aq) was needed to reach the equivalence point. Calculate: a) The concentration of the chloroacetic acid solution before the titration b) the pH of the chloroacetic acid solution before titration c) the pH of the solution at half equivalence point d) the pH of the solution at the equivalence point e) the pH of the solution when...
In the laboratory, a general chemistry student measured the pH of a 0.527 M aqueous solution of nitrous acid to be 1.797. Use the information she obtained to determine the Ka for this acid. Ka(experiment) =
Calculate the pH of a buffer solution that contains 0.25 M benzoic acid (C6H5CO2H) and 0.15 M sodium benzoate (C6H5COONa). (Ka = 6.5 x 10-5 for benzoic acid)
please answer both questions QUESTION 18 An aqueous solution contains 0.27 M ammonium chloride, NH4Cl. One liter of this solution could be converted into a buffer by the addition of 1.0.27 mol NH4Br 6.0.27 mol HBC 6.0.13 mol HCI 1.0.26 mol NH3 9.0.26 mol KCI QUESTION 19 A 29.9 ml. sample of 0.299 M methylamine, CH3NH2, is titrated with 0.331 M hydroiodic acid, HI at 25°C. (Xb for methylamine is 4.2 * 10-4) What is the pH at the equivalence...
Q: What is the pH of a solution containing 0.125 M KH2PO4 and 0.175 K2HPO4 Ka (H2PO4-) = 6.2 x 10-8 Ka (HPO42-) = 4.8 x 10-13 Q: A 0.15 M solution of a weak acid is 3.0 % dissociated. What is the Ka of this acid? Q: A solution of aspirin was prepared that is 0.16 M. The pH of this solution was measured to be 2.43. What is the Ka of aspirin? Q: A solution of formic acid...
Need help with this ASAP QUESTION 7 What is the pH of 0.15 M solution of acetic acid (HC2H302)? The Ka of acetic acid is 1.8 x 10-5. O pH = 3.5 O 5.6 pH - 2.2 W pH - 1.7 OpH - 2.8
A buffered solution with pH of 4.4 is made of 0.1 M Benzoic acid, HC-HOs, and 0.15 M Sodium benzoate, NaC;HO2. After an addition of 1.5 mLs of 6.0 M HCI to 250 mLs of the buffered solution, what is the resulting pH? Ka 6.6 x 10
A solution of 100. ml of .500 M Acetic Acid is titrated with .500 M sodium hydroxide. The Ka of acetic acid is 1.8*10^-5. Find the pH values at the given stages: a) before the addition of any NaOH. B) After 25.0 mL of NaOH added. C) At the equivalence point.