1) We will use the equation:
Here
and
Then
2) Now we will use:
3) At the maximum height v = 0 m/s
We will use:
, where x is the total height jumped.
Hence the armadillo goes = 0.865 - 0.589 = 0.276 higher than given.
A startled armadillo leaps upward, rising 0.540 m in the first 0.198 s. (a) What is its initial speed as it leaves the ground? (b) What is its speed at the height of 0.540 m? (c) How much higher does it go? Use g=9.81 m/s2.
Chapter 02, Problem 044 A startled armadillo leaps upward,rising 0.565 m in the first 0.192 s. () What is its initial speed as it leaeves the ground? (b) what is ts speed at the (e) How much higher does it go? Use g-9.81 m/s2 (a) Number (b) Number (c) Number Click if you would like to Show Work for this question: Open Show Work Units Units Units
deep water divers will experience much higher pressure than at the surface. At a depth of 20 m below the surface, what pressure does what exert on the drivers body? Use g= 9.81 m/s2
The value of g at the Earth's surface is about 9.81 m/s2. The the mass of the Earth = 5.98 x 1024 kg and the radius of the Earth is 6.37 x 106 m. 1) Calculate the value of g for a satellite that is orbiting in a circle at an altitude equal to 3 Earth radii. g =
The acceleration of gravity is 9.81 m/s How 'l is the tower? Answer in units of m. 004 10.0 points A mass of 0.22 kg is attached to a spring and is set into vibration with a period of 0.22 s. What is the spring constant of the spring? Answer in units of N/m 005 (part 1 of 6) 10.0 points Consider a pendulum of length 4.488 m. The acceleration of gravity is 9.832 m/s a) What is its period...
In a room where g = 9.81 m/s2, a hockey puck slides off the edge of a platform with an initial velocity of 18.0 m/s horizontally. The height of the platform above the ground is 5.00 m. What is the speed of the puck just before it hits the ground? The air resistance is negligibly small. 0 41.0 m/s 20.5 m/s 26.0 m/s 36.6 m/s 0 28.7 m/s
The acceleration of gravity is 9.81 m/s2 . Find the length of a pendulum that oscil- lates with a frequency of 0.15 Hz. Answer in units of m
. In this class, we will use the value of g-10 m/s2g-10 m/s2, or g-9.8 m/s2g-9.8 m/s2, when more precision is needed. According to your textbook, what is the typical variation of gravitational acceleration gg on the surface of the Earth? The value of gg ranges from m/s2m/s2 to m/s2m/s2 . A bowling ball rolls along a straight track with an average velocity of 11 cm/s for 20 seconds. How far does the bowling ball roll in this time? The...
given the information answer Common constants: 9.81 m/s2 = gravity on Earth's surface 343 m/s = speed of sound (air @ 20°C) 1440 m/s = speed of sound (water @ 20°C) 1.21 kg/mp = air density (20°C, 1 atm) 998 kg/m3 = water density (20°C, 1 atm) 1 atm = 1.01 x 105 Pa 3 x 108 m/s = c = speed of light (vacuum) 1.661x10-27 kg = p = atomic mass unit Specific Heats: 2040 J/(kg °C) Cwater =...
Statics Note: Use g = 9.81 m/s when required. 3. Consider the vector A whose magnitude is 12 m. (a) Express A in terms of its Cartesian components. (4) (b) Hence calculate the angles that A makes with the pos- itiver and y axes. (2) 400