Question

3. Write a balanced chemical equation for the following reactions: a. Combination of graphite (solid C) and oxygen gas to form gaseous carbon dioxide (6 points) CO+2014) — 00,(9) + b. Formation of chloramine (NH2Cl) gas and solid ammonium chloride via reaction of gaseous ammonia with chlorine gas. Include the phases of each compound (8 points). 6 NA (9) +20169) →NH, CI(9) + NH4Cl (s) 6NH (D c. Reaction of calcium chloride and sodium phosphate to form sodium chloride + and solid calcium phosphate. All species except for calcium phosphate are completely dissolved in water (8 points). Call + Nap NacIGH NaCaP(s) alculate the molar mass of the following compounds (6 points each): C-12.01.17 = 204.187 a. Benadryl, an antihistimine (C17H21NO)? H = 1.0078.21 = 21.1638 N: 14.00 - 14.00 0 = 15.9999415.999 255.- b. human insulin, a hormone protein that regulates metabolism (C257H383 N6507756? C=12.011-257 = 308 H=1.0078.383=385 N= 14.007.055 Go L 0=15.99.77= 1231

Answer 1

Balanced chemical Equation a) Carbon dioxide (g) Graphite (s) + Oxygen (g) - Ces) + 2018) - Coneg 6) Ammonia (g) & chlorine ig) - Chloramine (g) + ammonium Chloride 2NH3(g) t clig) - 2NH₂ clig) + NH₃ eles)

c) Calcium chloride - & Sodium Sodium phosphate chloride of calcium 026 phosphate 2 Naz (PO4) + 3 Cach - Ca, (PO4)2 + 6 Nach. Calculate Molar mass Molar mass of c = 12 g 419 . Molar mass of Cat H₂, No = (17x Mass of ct (21 x Mass of 4) + (x (1x Mass of Mass of N) of = (17 x 129) + ( 21 x 1g) + (1x 149 + (1x 16g). - 2049 +212 + 149 + 16g - 255g Molar mass of S = 329 ... Molar mass of C257 Haga N65 044 So = (257x Mass of c) + (3838 Mass of H) + (65% Mass of N) + (77x Mass of olt 16x Mass of s) - (257x12g) + ( 383 x 1g) + (65* 14 g) + ( 77 x 16g) + (6 x 329) - 30849 + 38 39 + 9 10 g + 12329 + 1929. 5801g