Question

A proton follows the curving path shown in red. The dotted gray circle is the kissing circle tangent to the path when the pro

0 0
Add a comment Improve this question Transcribed image text
Answer #1

A)

Parallel component = 0

B)

Perpendicular component,

F = mv^2/r

F = 1.7 x 10^-27 x (4.2 x 10^5)^2/0.07 = 4.28 x 10^-15 N

Add a comment
Know the answer?
Add Answer to:
A proton follows the curving path shown in red. The dotted gray circle is the kissing...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Problem 5.24 A proton follows the curving path shown in red. The dotted gray circle is the kissing circle tangent to the path when the proton is at location A. The proton is traveling at a constant s...

    Problem 5.24 A proton follows the curving path shown in red. The dotted gray circle is the kissing circle tangent to the path when the proton is at location A. The proton is traveling at a constant speed of 7.3 x 105 m/s, and the radius of the kissing drde is 0.04 m. The mass of a proton is 1.7 x 102 kg. Refer to the directional arrows shown at right when answering the questions below j out of the...

  • Please answer all parts! A proton follows the curving path shown in red. The dotted gray...

    Please answer all parts! A proton follows the curving path shown in red. The dotted gray circle is the kissing circle tangent to the path when the proton is at location A. The proton is traveling at a constant speed of 7.8 x 10 m/s, and the radius of the kissing circle is 0.03 m. The mass of a proton is 1.7 x 10 directional arrows shown at right when answering the questions below. kg. Refer to the h b...

  • A proton follows the path shown in (Figure 1). Its initial speed is v0 = 2.7×106...

    A proton follows the path shown in (Figure 1). Its initial speed is v0 = 2.7×106 m/s. What is the proton's speed as it passes through point P? Express your answer to two significant figures and include the appropriate units. 4.0 mm Vo -10 nC 3.0 mm

  • A charge particle enters a uniform magnetic field and follows the circular path shown in the...

    A charge particle enters a uniform magnetic field and follows the circular path shown in the drawing. f (a) Is the particle positively or negatively charged? O positive O negative O electrically neutral Why? This answer has not been graded yet (b) The particle's speed is 110 m/s, the magnitude of the magnetic field is 0.46 T, and the radius of the path is 960 m. Determine the mass of the particle, given that its charge has a magnitude of...

  • 8) A proton is placed at rest near a positively charged plate. The proton is released...

    8) A proton is placed at rest near a positively charged plate. The proton is released and travels in the positive x direction. The proton reaches a velocity of 85000 m/s at the point when the potential is zero. (mproton = 1.67 x 10-27 kg, et = 1.6 x 10-19 C) a) What is the electric potential at the positively charged plate? A X b) The proton then enters a 9 T magnetic field directed into the page. Choose the...

  • A proton enters a region of constant magnetic field, perpendicular to the fie and after being...

    A proton enters a region of constant magnetic field, perpendicular to the fie and after being accelerated from rest by an electric field through an electric potential difference of - 350 V. Determine the magnitude of the magnetic field, if the proton travels in a circular path with a radius of 21 cm. mt As shown in the figure below, when a charged particle enters a region of magnetic field traveling in a direction perpendicular to the field, it will...

  • As shown in the figure, an electron is fired with a speed of 3.73 x 10...

    As shown in the figure, an electron is fired with a speed of 3.73 x 10 m/s through a hole in one of the two parallel plates and into the region between the plates separated by a distance of 0.24 m. There is a magnetic field in the region between the plates and, as shown, it is directed into the plane of the page (perpendicular to the velocity of the electron). Determine the magnitude of the magnetic field so that...

  • A proton, traveling with a velocity of 3.1 × 106 m/s due east, experiences a magnetic...

    A proton, traveling with a velocity of 3.1 × 106 m/s due east, experiences a magnetic force that has a maximum magnitude of 6.6 × 10-14 N and direction of due south. What are the magnitude and direction of the magnetic field causing the force? If the field is up, then enter a number greater than zero. If the field is down, then enter a number less than zero. An α-particle has a charge of +2e and a mass of...

  • in magnitude the smaller the radius of the circle in magnitude the smaller the radius of...

    in magnitude the smaller the radius of the circle in magnitude the smaller the radius of the circle. sat a constant sped in a circular path, the acceleration of the ob s. Ian object trav Bin the se direction as the velocity of the object B) larger C) smaller of the velocity of the object Din she oppostie dinetion E) zero. a building,the door opens outward. If the hinges on the door are on your 6 As you are ieh...

  • Consider a ball of mass 0.110 kg being spun in a horizontal circle of radius r-0.50...

    Consider a ball of mass 0.110 kg being spun in a horizontal circle of radius r-0.50 m, as shown to the right. When the ball reaches an angular velocity (o) of 2.00 rad/s, it is given a constant angular acceleration of a- 2.00 rads. You can assume that the radius of the circular path followed by the ball remains constant during this acceleration. After precisely 3.00 seconds of this angular acceleration, the ball breaks off the string (a) In what...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT