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im fairly sure the answer should be 4 although ive been having trouble with these
In the balanced equation for the reaction of zinc with nitrate to produce Zn(OH)42 and ammonia under basic conditions, how ma
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Answer #1

oxidation half reaction   ---------------------------------       reduction half reaction

Zn-----> Zn(OH)4^2- ------------------------------------                   NO3^- -------> NH3

Zn+ 4H2O-----> Zn(OH)4^2-   --------------------------------              NO3^- -------> NH3+3H2O

Zn+ 4H2O+4OH^- -----> Zn(OH)4^2- +4H2O -------------            NO3^- +9H2O-------> NH3+3H2O+9OH^-

Zn+ 4H2O+4OH^- -----> Zn(OH)4^2- +4H2O --------------------      NO3^- +9H2O-------> NH3+3H2O+9OH^-

Zn+ 4H2O+4OH^- -----> Zn(OH)4^2- +4H2O +2e^- -------------------- NO3^- +9H2O +8e^- -------> NH3+3H2O+9OH^-

                  4Zn+ 16H2O+16OH^- -----> 4Zn(OH)4^2- +16H2O +8e^-

                      NO3^- +9H2O +8e^- -------> NH3+3H2O+9OH^-

                -------------------------------------------------------------------

                 4Zn + NO3^- +6H2O+7OH^- ----------> NH3 + 4Zn(OH)4^2-

6 water molecules are present at reactant side >>>>answer

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