Question

A cube of edge length 2.9 m is inside a region of a uniform electric field(shown below). What is the electric flux through the front face if the electric field in newtons per coulomb, is given by a) 61 c) what is the total flux through the cube for each of the above fields

Answer 1

Because Area vectors of front face. Vector A = a^2 I = (2.9)^2 I m^2 because a = 2.9 m vector A implies (8.41 i) m^2 a) electric field vector E_1 = 6i electric flux, phi_1 = vector E middot vector A = (6i) middot (8.41 i) wb implies 50.46 wb b) when, electric field, vector E_2 = -6i + 5k electric field, phi_2 = vector E_2 vector A = (-6i + 5k) middot (8.41 i) implies -50.46 wb c) total flux through the cube for each the above cosh will zero. (since cube is closed loop having no charge inside cube)