An electric field given by E→ = 5.2 î - 9.5(y2 + 5.8) ĵ pierces the Gaussian cube of edge length 0.980 m and positioned as shown in the figure. (The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux through the (a) top face, (b) bottom face, (c) left face, and (d) back face? (e) What is the net electric flux through the cube?
An electric field given by E→ = 5.2 î - 9.5(y2 + 5.8) ĵ pierces the...
An electric field given by E→ = 4.4î - 7.4(y2 + 1.6)ĵ pierces the Gaussian cube of edge length 0.320 m and positioned as shown in the figure. (The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux through the (a) top face, (b) bottom face, (c) left face, and (d) back face? (e) What is the net electric flux through the cube?
please help i don't understand how solve using gauss' law. An electric field given by E 5.2i - 7.4(y2 3.2)j pierces the Gaussian cube of edge length 0.340 m and positioned as shown in the figure. (The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux through the (a) top face, (b) bottom face, (c) left face, and (d) back face? (e) What is the net electric flux through the...
An electricfeld given by E 6.6i-11y+7.4)j pierces the Gaussian cube of edge length 0.660 m and positioned as shown in the fgure. (The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electricflux through the (a) top face, (b) bottom face, (c) left face, and (d) back face? (e) What is the net electric flux through the cube? Gaussian surface (a) Number Units (b) Number Units (c) Number Units (d) Number Units...
For the situation in problem 23.2, find the flux (in Nm2/C) through the y = a (right) face of the cube of side a = 2.2 musing an electric field with components in N/C of Ex = 4.0, Ey = -2.0(x/a - 3.0), and Ez = 0. (2 sig. figs.) through the surface. 2 An electric field given by E 4.0i- 3.0(y2 + 2.0)i pierces a Gaussian cube of edge length 2.0 m and positioned as shown in Fig. 23-7....
The figure shows a closed Gaussian surface in the shape of a cube of edge length 1.8 m, with one corner at x1 = 4.4 m,y1 = 4.3 m. The cube lies in a region where the electric field vector is given by E→ = - 2.4 î - 3.2 y2 ĵ + 3.4 k̂ N/C, with y in meters. What is the net charge contained by the cube?
A cube of edge length 2.9 m is inside a region of a uniform electric field(shown below). What is the electric flux through the front face if the electric field in newtons per coulomb, is given by a) 61 c) what is the total flux through the cube for each of the above fields
A cube of side L-3.2 m lies in a region where the electric field is given by E-2 7+5.4)i -4.0k N/C. We wish to find the net electric flux through the cube by first calculating the flux through each of (a) What is the flux through the left face of the cube? N-m2/C (b) What is the flux through the right face of the cube? N m2/c (c) What is the flux through the top face of the cube? (d)...
Question 8 2 pts An electric field given by E = 2x y2 i + yx?j + 3 zy? k pierces the Gaussian cube shown below. How much charge, in nC, is enclosed in the cube? (E is in N/C,,y and zin meters). Take En = 8.85 x 10-12 C2/Nm2. y (1,3,0) (4,3,0) (1,3,3) (4, 3, 3) (4,0,0) x (1,0,3) (4,0.3) Equations: I enclosed =o total +0 left +0 from bottom top back right E = 8.85 x 10-12 Nm...
The figure below represents the top view of a cubic surface in a uniform electric field oriented parallel to the top and bottom faces of the cube. The field makes an angle θ=40o with side and the area of each face is A . a) Draw an area vector A for each face, , , , b) Label the angle between the area vector A and the electric field vector E for each face. c) Find flux through each face....
22. Figure P24.22 (page 742) represents the top view of a cubic gaussian surface in a uniform electric field E ori ented parallel to the top and bottom faces of the cube. The field makes an angle 0 with side 0, and the area of each face is A. In symbolic form, find the electric flux through (a) face 0, (b) face 2, (c) face 3, (d) face 4 and (e) the top and bottom faces of the cube. (f)...