a)
net force acting on 7 uC is vector sum of individual forces due to 6uC and 8 uC.
force due to 6 uC is repulsive hence directed to the 8 uC
Force due to 8 uC is also repulsive on 7 uC hence directed to the 6uC
Now Net force is given by
F = F8 - F6
F = k q q8 / r^2 - k q q6/ r^2
F = 9*10^9* 7*10^-6*8*10^-6 / 0.09^2 - 9*10^9* 7*10^-6* 6*10^-6/ 0.09^2
F = 15.556 N
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b)
Since force between act due to 8uC is greater than 6 uC so net force is towards 6 uC.
option (b) is correct
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do comment in case any doubt, will reply for sure.. Goodluck
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