use:
pH = -log [H+]
2.62 = -log [H+]
[H+] = 2.399*10^-3 M
HA dissociates as:
HA -----> H+ + A-
1.19*10^-2 0 0
1.19*10^-2-x x x
Ka = [H+][A-]/[HA]
Ka = x*x/(c-x)
Ka = 2.399*10^-3*2.399*10^-3/(0.0119-2.399*10^-3)
Ka = 6.057*10^-4
Answer: 6.06*10^-4
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