use:
pH = -log [H+]
2.66 = -log [H+]
[H+] = 2.188*10^-3 M
HA dissociates as:
HA -----> H+ + A-
1.85 0 0
1.85-x x x
Ka = [H+][A-]/[HA]
Ka = x*x/(c-x)
Ka = 2.188*10^-3*2.188*10^-3/(1.85-2.188*10^-3)
Ka = 2.59*10^-6
Answer: 2.59*10^-6
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