assume weak acid = HA
HA <-----------> H+ + A-
initially
[HA] = 0.0199 M
pH = 2.37
[H+] = 10-pH = 10-2.37
[H+] = 0.00426 M
at equilibrium
[H+] = [A-] = 0.00426 M
[HA] = 0.0199 - 0.00426 = 0.01564 M
Ka = [H+] [A-] / [HA]
Ka = [0.00426][0.00426] / [0.01564]
Ka = 1.17 x 10-3
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