Question

Is trom surface of Delectromae to ejectelee ragnetic energy required a electrons from surt Tungsten me talis 440 kJ/mol slect

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Answer #1

Total energy = threshold energy + kinetic energy

Given, wavelength of light absorbed (\lambda) = 200nm

= 200×10-9 m

= 2×10-7 m

a)

Threshold energy = 440 KJ/mol

= (440×103/6.02×1023)

= 7.31×10-19 J/electron.

b)

Total energy = h\frac{c}{\lambda}

= (6.626×10-34×3×108/2×10-7)

= 9.94 ×10-19 J/electron.

C)

Now, Kinetic energy of each electron

= (9.94×10-19 - 7.31×10-19 ) J

= 2.63×10-19J.

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