What is the concentration of bromide, in ppm, if 169.32 g MgBr2 is dissolved in 1.47 L water. Record your answer in scientific notation to 3 significant figures.
Mass of MgBr2 = 169.32 gm
Molar mass of MgBr2 = 184.113 g/mol
Concentration of MgBr2 = 169.42 gm / 184.113 g/ml x 1.47 L = 0.625 M
Every MgBr2 has two bromine atoms. When it dissolves, it produces two equivalent of bromine atoms.
Concentration of bromide ion = 0.625 M x 2 = 1.2519 M
Hence 1.2519 M of bromide ions are present in the solution
What is the concentration of bromide, in ppm, if 169.32 g MgBr2 is dissolved in 1.47...
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