Q. Answer:-
Given that , the chemical in water has a concentration of 30 ppm, that means 30 mg of chemical is dissolved in 1L of water.
We have to calculate the quantity of water needed to have 1 g of this chemical.
First we convert 1 gm into milligram, multiplying the value by 1000. Thus
1 gm = 1 × 1000 = 1000 mg
Since, 30 mg of chemical is dissolved in 1L of water, thus, 1000 mg chemical is dissolved in
(1000 mg × 1L ) ÷ 30 mg
= 33.3 L
Thus the answer is 33.3 L
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