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Q6. A block of mass 1 kg is placed on a truck which accelerates with acceleration 5 m/s. The coefficient of static friction between the block and truck is 0.6. The frictional force acting on the block is: C) 5.88 ND) 4.6 N E) None
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Answer #1

Frictional force(f) = coefficient of frictional force(u) x normal force (N)

From free body, diagram normal force(N) =mass(m) *gravity(g)

Therefore frictional force(f) =coefficient of frictional force (u) x. Mass(m) x gravity(g)

lock CochkiCent ive knets

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