Question

3. Which of the following aromatics would react most rapidly and which would react most slowly with Brz/FeBr;? Justify your answer and predict the structure of the major product for the fastest reacting substrate. 2H OME OCH3 COH Don Goon good on a H2C NO2

I don't understand how to solve these type of questions, so I'd appreciate it if you could show me your reasoning, not just the answer please.

Answer 1

3 Higher the electron density in ring, More reactive the ring will be towards electrophillic aromatic substitution t Election withdrawing groups decreaus the electron density in ring and deactivate the ring towards electrophillia o caromatic sube aromatic substitution reaction. The most reactive compound with Br. Ferra is shown below. - CH₂ Here two electron donating groups are present. The ring is activated due to presence of two electron donating groupe. CH₃ (Most Rec OCH OCH 3 Bry/FeBYa 7 CH₃ Y para position is Blocked Matos product) | - ich is more activating. It is ortho Para directing group. Со он - Least Reactive compound with Br2 Febrz 2 - Here two strong election withdrawing groups are present and the ring is deactiva