Question

1) Explain why 1-butanol, CH3CH2CH.CH-OH, is soluble in water, while heptane, CH(CH) CH3, is not. "Like dissolves like" IS NOT the answer. 2) In chemistry 121 you learned three different definitions of oxidation and reduction, one of which has little or no application to organic chemistry, Write the two definitions of an oxidation AND the two definitions of a reduction that are used to describe redox processes involving organic molecules. 3) There are three oxidizing agents used in this lab. Write the name and the formula for two of the three. 4) In redox reactions, what ALWAYS happens to oxidizing agents? 5) Write the definition of physical property AND explain how one physical property is used in the completion of this lab.

Answer 1

Please refer below image it will help you

The common oxidising agents used in lab are PCC, PDC, CrO3 , K2Cr2O7 , KMnO4 etc.

0 l-butanol is soluble in water but heptano is not the main reason behind this is that in butanol we have o group that is polay and that makes hydrogen bonding with H2O hence it is soleble, but in heptane it is non polar so no hyd xog on bonding © oxidation → loss of hudrogen -CH=CH-CH3 rol CH3-CO-CH3 Reduction Gain of hudrogen СИs- сня си, пееn СИз- Иг -си з oxidation – Gain of oxygen - Rc-n -R-C-on. rod coction a loss of oxygen -R-con R-043 © Redox reaction is reaction in which both oxidation and reduction takes place oxidizing agent is the one which gets reduced 4NH3 +502 4 No + 6H2O oxidizing Redh agent