Homework Answers
a] work done = - area under curve
= - [ 0.25*0.4 + 0.5*(0.25+0.05)*(1-0.4) +0.2*0.05 + 0.5*(0.05+0.2)*(2-1.2)]
= - 0.3 J
B] change in kinetic energy = work done
= - 0.3 J
c] change in KE = - 0.3
0.5mv^2 - 0.5mu^2 = - 0.3
0.5*0.62*v^2 - 0.5*0.62*3^2 = -0.3 and v has to be negative as it is moving in -x direction.
v = -2.83 m/s i^
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