Question

In the figure, three 0.05 kg particles have been glued to a rod of length L = 12 cm and negligible mass and can rotate around a perpendicular axis through point O at one end. How much work is required to change the rotational rate (a) from 0 to 20.0 rad/s, (b) from 20.0 rad/s to 40.0 rad/s, and (c) from 40.0 rad/s to 60.0 rad/s? (d) What is the slope of a plot of the assembly's kinetic energy (in joules) versus the square of its rotation rate (in radians-squared per second-squared)?

is this correct solving

Chapter 10, Problem 062 Your answer is partially correct. Try again. In the figure, three 0.05 kg particles have been glued to a rod of length L = 12 cm and negligible mass and can rotate around a perpendicular axis through point o at one end. How much work is required to change the rotational rate (a) from 0 to 20.0 rad/s, (b) from 20.0 rad/s to 40.0 rad/s, and (c) from 40.0 rad/s to 60.0 rad/s? (d) What is the slope of a plot of the assembly's kinetic energy (in joules) versus the square of its rotation rate (in radians-squared per second-squared)? a-t-del-a-|

Answer 1

m= 0.osky 1=1 12X10-2 m dz) = 133= 4019-27 * moment of inertia (7) nooo = (ma+*+mXm84 * = md +47 92+gim t 2 14mote 1 = 1440-059 (42107= :12 X1D-2 kg. one work = tf(wi? - w,) = (1.12 10-2) * |(20) 2–0) = 10-2243 ☺ work = of I ( Wiki – mi?) = * 11.12.3194)•(16092 2003)= 71-1207] ® Work 3 of 4 (1-12 30.2) (leo1280*) = 70-68.27) kifa & Iw2 4 Wade que Shopa The = {1= n(1-12 000-3) vahele Islope = 5.6810-4 yos27