Question

Can someone answer c and d?

Physics 8B 1- Charge and Coulomb's Law rev 4.0 . Two charges QA QB +Q are held fixed on the y-axis at (0, 3d) and (0,-3d). A third charge, Qc = +Q, is released from rest on the x-axis at (4d, 0). eA QB a) Q: Which way will Qc move? Explain b) Q: Describe the motion of Qc. Does it speed up? Slow down? Turn around? Where is it fastest? Etc. c) P: Find the force (mag. and dir.) on Qc- Q&P: Repeat a) -e) for the case where Q20.

Answer 1

Here, Cose: 4.d = 4 5d 5 and electric field at the position of charge Oc will be; 30 01. ka el 25d² 25 2 (50) 2 and, E = KQB - KQB = ka 3d And, Net electric field at point c will be; E = EA. Cose + E2.630 = ka 1+ko (4) = 8 ka 25 d² 15 125 d² © Solution. F = Qe E = O 8 KQ Sko 2502 0 22 15 de ond, direction: Along positive x-axis. (- >> @ If, Q = -20 . Then Ac will move along negative x-axis. Because, negatively charged Qc will be attracted by positively charged QA and QB. • Oc will speed-up. And, Qc will be moving fastest at the origin. Force on Qe= - 20 magnitude, F = lal. E = 2018 kq) 125 d² J hilo Direction: Along negative X-axis. (4)