Q2.
i) Since the sample size is less than 30 hence right tail test is applied here
Alpha=0.05= Level of significance
Assumption:
i) Randomly selected Sample
ii) Since it is from a large population it is approximately normal
ii) n<30 then it follows t distribution
ii) The hypotheses are:
3) Test Statistic
P value :
P value associated with T statistic and Degree of freedom=n-1=28-1=27 as 0.088
4). Since P value =0.088 > 0.05( Level of significance) hence we fail to reject the null hypothesis.
5) Conclusion:
Since we fail to reject the Ho (Null hypothesis), then we conclude that we do not have enough evidence to support the claim that the new campaign has increased the average no of customers.
Q3.
One sample Z tail proportion test is applied here.
2) The hypotheses are:
Hence it follows left tail test for proportions
3) Test statistics
P value:
P value associated with the Z score as 0.258 can be computed from Z statistic table or by the calculator.
4) The P value=0.258>0.05(Alpha) Hence we fail to reject the null hypothesis.
5) Conclusion:
Since we fail to rejctthe null(Ho) Hypothesis hence we conclude that we do not have enough evidence to support the claim.
Q4.
1) The Level of significance =0.01( Alpha)
Assumption :
i) The sample was taken from a large population.
ii) n>30 hence it follows a normal distribution
iii) The sample is randomly selected
2) The hypotheses are:
Hence Right tail T-test is used here since sample standard deviation is given
3) Test statistic
P value:
P value associated with the T statistics as almost 0.00001=0
4) Since the P value=0< 0,10 hence we reject the null hypothesis .
5) Since we reject the null hypothesis we conclude that we do have enough evidence to support that their mean was higher than of competitors.
a grocery store owner wants to know if a new marketing campaign will Take+home+Exam+1-SPR2019) Mailings ReviewView...
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