Question

Provide a generic mechanism for an aldol condensation. DRAW structures for the 16 possible products.

Answer 1

Aldal Condensation : It is the general reaction of Aldehycle and Ketone having at least 22-14 . It takes place in the presence of dilute Ned4 (not come Noy or faring Base Like R-00). * In the presence of Strong base the reaction becomes reversible. Here , attack of reachephile on the carbonyl centre/ Carbon is the Ros (Route determining Aten), Naoh dil Chest Noër diet, OK (thes Hydrogen is a the bit acidic, because of resonance) s -Mt Ch=Ć-M. ed on ag=EH हु -nc- H CH 9s (Attack of Nucleophile is the RDS) : / B-hydrony Aldol aldehyde) Pagarch=ćucu s re-i of 4-4-2 Encu 6,68 + H₂O _ = CH Che e or (Base Catalysed Dehydralien 6,68 (Eliminatica of strung Besa like Etool Ghool - unimolecular via used, then reaction becomes reversible Conjugate Ball The Conjugate Base). Ha a {to En-cho Good learning group c- c oc-c=c- + C . Starting reactant). (6,Co) |

еңесно + cң - ", -но ", Here Two simple & Cross aldol products are formed. Сң-сно cң-ба-но (с-сно +1 CH-CH, 2-4 си, н о , сен- 1 си, -д - en—си, -но 9 10 — си --О, - си, СК -н- -но сч, -сі — си = 04-но то | ск, -енги-шо) *но |,-f=CH-C4 -чи се, й од до + си, сле но и е О, -н-н-се, нь 51 CHO 1 Ch CH = CHC CH=CH2O + Chole of Here also u possible products are formed (2 simple to cross Aldol Products) CH₂ – CH = CH-CHO 3-simple CH-CH=CH-d-up) Cherche-grens Adobe - Enes I Aldol Products hc-c= 4 -сно . Product

Intramoleculer Aldol. Condensation - fen D G On (B-hydroxy Ketme) unsaturated Ketone I CH₃CM Checho + 1. Two Cincho cross fimple Aldol on A Condensation Producto Tus simple Aldol a гс-сk = A -но | --=c-dt 0 Ich-c-ch-cho -cho -Chc=h-cho conce-an- + 8y-cho Here a different crops aldol Products can be made as they are 3 different a Carbon position nado as they are - I chy-che-ch_&_H=CH-C , CH-CH 2 -CH=CH-CH. --=CH-CH3. . : Chce