given that
focal length f = 5 m
a) if x = 15 m
from the relation
1/x+1/x' = 1/f
1/x' = 1/f-1/x
x'= xf/x-f
x' = 15*5/15-5 = 7.5 m = image distance
magnification m = -7.5/15 = -0.5
image is inverted
b) if x = 2 m
x' = 2*5/2-5 = 10/-3 = -3.33 m
magnification = 3.33/2 = 1.665
image is upright
c) if x = 5m
object is located at infinity
x' = imfinity
d) if x' = 5m
x = x*f/x'-f
x = infinity
Problem 3 A lens with a focal length of 5 meters is used to look at...
A lens with a focal length of 5 meters is used to look at an object this is x meters away, find the image distance, magnification, and whether the image is inverted or upright for the following values of x: a) x = 15 meters b) x = 2 meters c) if the object is placed at 5 meters away, find the image distance only. d) if the image distance is 5 meters away, find the object distance only.
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An object is 22.0 cm to the left of a lens that has a focal
length of +8.50 cm. A second lens, which has a focal length of
-29.0 cm, is 5.80 cm to the right of the first lens.
(a) Find the distance between the object and the final image
formed by the second lens.
(b) What is the overall magnification?
Please help with parts A and B. Thanks!
An object is 22.0 cm to the left of a...
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