Question

Problem 3 A lens with a focal length of 5 meters is used to look at an object that is x meters away, find the image distance,
0 0
Add a comment Improve this question Transcribed image text
Answer #1

given that

focal length f = 5 m

a) if x = 15 m

from the relation

1/x+1/x' = 1/f

1/x' = 1/f-1/x

x'= xf/x-f

x' = 15*5/15-5 = 7.5 m = image distance

magnification m = -7.5/15 = -0.5

image is inverted

b) if x = 2 m

x' = 2*5/2-5 = 10/-3 = -3.33 m

magnification = 3.33/2 = 1.665

image is upright

c) if x = 5m

object is located at infinity

x' = imfinity

d) if x' = 5m

x = x*f/x'-f

x = infinity

Add a comment
Know the answer?
Add Answer to:
Problem 3 A lens with a focal length of 5 meters is used to look at...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A lens with a focal length of 5 meters is used to look at an object this is x meters away, find the image distance, magn...

    A lens with a focal length of 5 meters is used to look at an object this is x meters away, find the image distance, magnification, and whether the image is inverted or upright for the following values of x: a) x = 15 meters b) x = 2 meters c) if the object is placed at 5 meters away, find the image distance only. d) if the image distance is 5 meters away, find the object distance only.

  • 1.) An object is placed in front of a diverging lens with a focal length of...

    1.) An object is placed in front of a diverging lens with a focal length of 17.7 cm. For each object distance, find the image distance and the magnification. Describe each image. (a) 35.4 cm location _____cm magnification _____ nature real virtual upright inverted (b) 17.7 cm location _____  cm magnification _____ nature real virtual upright inverted (c) 8.85 cm location _____ cm magnification _____ nature real virtual upright inverted 2.) An object is placed in front of a converging lens...

  • An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length o...

    An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length of 30.5 cm. A diverging lens with a focal length of-20.0 cm is placed 110 cm to the right of the converging lens. (a) Determine the position of the final image. distance location to the right , of the diverging lens (b) Determine the magnification of the final image 128.4 Your response differs from the correct answer by more than...

  • A diverging lens has a focal length of magnitude 21.2 cm. (a) Locate the images for...

    A diverging lens has a focal length of magnitude 21.2 cm. (a) Locate the images for each of the following object distances. 42.4 cm distance      cm location      ---Select---in front of the lensbehind the lens 21.2 cm distance      cm location      ---Select---in front of the lensbehind the lens 10.6 cm distance      cm location      ---Select---in front of the lensbehind the lens (b) Is the image for the object at distance 42.4 real or virtual? real virtual     Is...

  • A diverging lens has a focal length of magnitude 22.6 cm. (a) Locate the images for...

    A diverging lens has a focal length of magnitude 22.6 cm. (a) Locate the images for each of the following object distances. 45.2 cm distance cm location (behind or in front of lens) 22.6 cm distance cm location (behind or in front of lens) 11.3 cm distance cm location (behind or in front of lens) (b) Is the image for the object at distance 45.2 real or virtual? Is the image for the object at distance 22.6 real or virtual?...

  • An object is 22.0 cm to the left of a lens that has a focal length...

    An object is 22.0 cm to the left of a lens that has a focal length of +8.50 cm. A second lens, which has a focal length of -29.0 cm, is 5.80 cm to the right of the first lens. (a) Find the distance between the object and the final image formed by the second lens. (b) What is the overall magnification? Please help with parts A and B. Thanks! An object is 22.0 cm to the left of a...

  • A diverging lens has a focal length of magnitude 16.6 cm. (a) Locate the images for...

    A diverging lens has a focal length of magnitude 16.6 cm. (a) Locate the images for each of the following object distances. 33.2 cm distance      cm location      16.6 cm distance      cm location      8.3 cm distance      cm location      (b) Is the image for the object at distance 33.2 real or virtual? real virtual     Is the image for the object at distance 16.6 real or virtual? real virtual     Is the image for the object at distance...

  • An object is 1.95 m to the left of a lens of focal length 0.92 m....

    An object is 1.95 m to the left of a lens of focal length 0.92 m. A second lens of focal length -3.6 m is 0.4 m to the right of the first lens. a) Find the distance between the object and the final image formed by the second lens. (in m) b) What is the overall magnification (with sign)? c) Is the final image real or virtual? real virtual d) Is it upright or inverted? 1. upright 2. inverted

  • A real object is 13.6 cm to the left of a thin, diverging lens having a focal length of magnitude 24.5 cm.

    A real object is 13.6 cm to the left of a thin, diverging lens having a focal length of magnitude 24.5 cm. (a) is the sign of the focal length negative or positive? negative positive (b) Find the image distance. (c) Find the magnification. (d) State whether the image is real or virtual. real virtual (e) State whether the image is upright or inverted. upright inverted

  • An object is placed 100cm in front of a lens of focal length 50cm. A lens...

    An object is placed 100cm in front of a lens of focal length 50cm. A lens of focal length -20cm is placed 90cm beyond the first lens. a) Where is the final image located? b) Is this a real or virtual image? c) What is the magnification of the lens combination? d) Is the final image inverted or upright? e) Is the final image bigger or smaller than the object?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT