Question

A lens with a focal length of 5 meters is used to look at an object this is x meters away, find the image distance, magnification, and whether the image is inverted or upright for the following values of x:

a) x = 15 meters

b) x = 2 meters

c) if the object is placed at 5 meters away, find the image distance only.

d) if the image distance is 5 meters away, find the object distance only.

Answer 1

Given: - Focal length of lens (t) = 5m. since the focal length is given as the the lens is conven lens. - For Conven lens, object (u), image (V) distances are related by magnification is given by M. Ž. hia Imase height: hot object height.

lens. AI 2F 26 F quite Calendent (a) n = 15m, a uz 15m. $.$+ » Ś + ss fra *- => [va 7.5m. Ma - - - = - =-0.5 object is reduced to half of its site and it is invested Eve sigh). (b) w zm, » us 2m. $ * * * lens - šo ft 2 - 3 - a lv . - 3.33m are sign represents imase is on same side as the object. ME - = -43.33) 2 +1.66 times and object is magnified by 1.66 the image is upright.

a object is placed sm away a) nasm, 22 ne smi ţ but » }=th » Vzoo. Image is never formed. Imase distance asma) a vz.sm. d) 3) Ķ = =42.00 object placed at infinity distance would form imase at focal point of lens.