Question

For the circuit shown below, € = 16 V, L = 5.5 mH, and R= 6.512. After steady state is reached with S. closed and Sopen, at t = 0, S2 is closed and Sy is opened. Determine (a) the current through L att = 0, (b) the current through L at t = 3 x 10-4 s, (c) the voltage across R on the right at t = 3 x 10-4 s, and (d) the rate at which current through L changes at t = 3 x 10-4 s. R NN 0000 Hint a. The current through L at t = 0 is 2.46 A. Additional Hints for (a) b. The current through L at t = 3 × 10 -4 sis 1.726 VA. Additional Hints for (b). c. The voltage across R at t = 3 × 10 -4 sis 11.223 Additional Hints for (c) d. The rate at which current through L changes at t = 3 x 10-4 sis * A/s. Additional Hints for (d). Message instructor about this question

Answer 1

a) Initially S₁ is closed and S₂ is open , when steady state is reached current through L is

16 = 2.462 A

At time $t=0$ , the switch S₁ open and S₂ is closed, now current through L is

10 = 2.462 A

b) At time

t=3*10-45

Current through L is  

(1/1ਖ- =-

i = (eRt/L) = 162-6.513-10-4 /5.5*10-3 = 1.727 A

c)

At time

t=3*10-45

Voltage across L is  

V = E(e-Rt/L) = 16e -6.543410-4/5.5*10-3 = 11.223 V

d)

At time

t=3*10-45

Voltage across L is equal to voltage across R

Vi= VR

* = р. IP

iR di dt 1.727 * 6.5 5.5 * 10-3 = 2 = 2.041 * 103 A/S