Question

Question 26 of 26 Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pbl, (s)+2NH, NO, (aq) Pb(NO) (aq) +2 NH,1(aq)- What volume of a 0.650 M NH4I solution is required to react with 587 mL. ofa 0.540 M Pb(NO3)2 solution? volume: 669.6 ml. How many moles of Pbl2 are formed from this reaction? mol Pbl moles: 0.31698 erms of use contact us help about ua pracy policy careen MacBook Pro Q Search or enter website name & 9 7 6 O P T Y U L G J K ? > B M CO IN H

Answer 1

x Yolume il molarity = moles volume in I moles of 0.540 M Pb(NO). - molarity XY = 0.540 x 0.587 = 10.316 moles POCNO3). As per Stoichiometry Imole Pb(Ng reacts with 2 moles NH 4 I i. 0.316 moles POCN0g), = 2 x 0.316 moles NH4I = 0.632 moles molarity of NH4 I Solutions 0.650M => 0-650 = 0.632 moles NHY I vol in L . Volume = 0.972 L 972mL (b) As per Stoichiometry. moles of Pb Iz formed a moles of Pb(NO3)2 reacted = 10:316