solve fore the theta of velocity and x(all distance units are in meters)
Solution,
Considering motion along vertical direction,
vy^2 = uy^2 - 2 g (h2 - h1)
0 = [ 16 sin (theta)] ^2- 2*9.8* (6-4)
0 = [16 sin (theta)] ^2- 2*9.8*2
theta = 23 degree
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time taken to cover this vertical distance
t = uy/ g
t = 16 sin 23 / 9.8
t = 0.64 seconds
Considering motion along horizontal
x = 16 cos (theta) t
x = 16 cos 23* 0.64
x = 9.426 m
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do comment in case any doubt, will reply for sure.. Goodluck
solve fore the theta of velocity and x(all distance units are in meters)
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